Thanks brother, and your kind words are always appreciated.
That sounds logical enough, however I believe the critical component in play here is bullet yaw coming out of the barrel, and how every different bullet has different amounts of yaw leaving the barrel.
Once the bullet clears the muzzle, a force called "yaw" comes into effect. Air friction combined with centrifugal force will cause the bullet to yaw and go into a spiral, reaching a diameter as large as a few inches. As the bullet travels down range the gyro effect from the spinning bullet will eventually dissipate yaw from which point on, the bullet will remain on a straight path and drop due to gravity. The point at which the yaw disappears is when the bullet "goes to sleep, or fully settles. The longer the bullet, the farther the bullet must travel before the spiral will dissipate.
Bullet length, weight, and RPM all determine the size of the yaw spiral, but for the sake of this topic..it's the bullet length were talking about b/t .223 bullets. The longer the bullet is in relation to the diameter, the larger the yaw spiral will be in diameter...thus The longer the bullet, the farther the bullet must travel before the spiral will dissipate.
Simple version.... envision spinning a toy top- at first its over spun and spirals, slows a bit then settles into a stable rotation on a single point, if it slows beyond a certain rpm, it wobbles and then tumbles.
Lastly here is a graphic that kinda illustrates my premise from above...
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