Originally Posted by
lysander
1) There are two things required for proper operation, you have to have enough momentum and energy, and they are related, but different. Since the mass is fixed, the is a minimum velocity to achieve minimum momentum.
2) The average velocity is not a very good assumption. That would assume the acceleration is constant, it isn't, the initial acceleration is significantly higher in the beginning and drops as the volume increases.
3) Extraction is not what we are worried about here. The timing at the initiation of unlocking is the important thing. If the chamber pressure is forcing the lugs against the barrel extension there is a torsional load on the bolt, if the two forces are balanced there is no twisting load on the bolt. So, the time interval we are interested in the first 0.070 inch of carrier travel. When the bolt carrier moves rearward 0.070" the cam pin enters the helical portion of the cam track and begins to twist the bolt. That point is approximately when the cavity pressure just reached its maximum value. In order to reduce the torsional load on the bolt requires the time to this maximum has to be increased 0.5 ms. You cannot slow the carrier down that much and still get it to cycle.
4) No, as stated the acceleration is not constant. It starts very high and about half way through the cavity pressurization, it drops considerably. By the time extraction starts, the acceleration is just starting to go negative, as the carrier cavity pressure is venting, the carrier has picked up the mass of the bolt and case and must transfer momentum to them, and there is the drag force from the case/chamber.
5) First of, gas flow through a tube cannot move at supersonic speed, it's maximum speed is restricted to Mach 1, period.
The point where the yellow line (port-barrel interface) rises from zero is when gas first enters the gas tube. The point where the black line (cavity/key interface) rises from zero is when the gas starts to exit the gas tube. The time interval between these two points is about 0.2 ms.
The gas tube is 7.5 inches long.
The speed the gas is traveling is:
v = d/t
d = distance, 7.5 inches
t = time, 0.2 ms 0.0002 seconds
v = 7.5/.0002 = 37,500 in/sec = 3125 fps.
Speed of sound is dependent of the temperature of the gas. The gas temperature in the tube is around 2500 degrees C, therefore, the velocity for Mach 1 at this temperature is around 3463 fps. If you reverse the calculations the time require for gas at 3463 fps to go 7.5 inches is 0.18 ms. Almost exactly what the graph shows.
EDIT: AN ASIDE: A few more things more about 16 inch carbine systems:
The muzzle velocity of M855 from a 14.5" barrel is officially listed as 2970 fps. From a 16" it will be faster as the bullet is still accelerating. For simplicity sake, let's assume the bullet averages 2900 fps for the last 1.5 inches of barrel. How long will it take for a bullet at that speed to travel 1.5 inches?
d =v x t
v = velocity, 2900 fps, or 34,800 inches/second
d = distance, 1.5 inches.
solve for t.
d/v = t
1.5 / 34800 = 0.04 milliseconds, 40 millionths of a second.
That small a time interval is not going to matter in how long the 'gas tube is pressurized'...
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