I believe MarkM's sig line is appropriate for this thread!
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I believe MarkM's sig line is appropriate for this thread!
Even if it is... that is 104,898.207g
Another eye opener.
BTW Your math is good. My math is easier. If we have delta v on given distance with constant acceleration then average v=v0-dv/2Then with known distance we get time. Gives same result at the end. (I had always tendency to oversimplify, that is why they kicked me out from Physics at University)
BTW2 But we know, we do not have constant acceleration due to changing pressure curve that changes force applied.
Last edited by montrala; 12-14-11 at 19:45.
Montrala
I'm sponsored competition shooter representing Heckler&Koch, Kahles, Hornady and Typhoon Defence brands in Poland, so I can be biased
http://montrala.blogspot.com
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Now THIS is my kinda physics experiment!!!![]()
-VERITAS VINCIT-
What the hell are you guys typing?!?! I'm pretty sure whatever it is, it's violating the forum rules for geekness...
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Ugghhh I just finished the last final exam of my college senior year today and I come to the forum for a little relaxation and light reading...and I see this![]()
Wow...Though isn't the bullet accelerating exponentially during that trip, so the dwell time is slightly longer than that?
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